regex - Java - Split string based on space and single quote but ignore two single quotes -


i want split string using space , single quote. 2 single quotes should ignored.

input:

name eq 'a''b'

output should be:

name  eq  a''b

i tried use 

[^\\s\"(?<!')'(?!')]+|\"[^\"]*\"|(?<!')'(?!')[^(?<!')'(?!')]*(?<!')'(?!')"

but not work.

the following 1 should suit needs:

'(?:[^']|'')+'|[^ ]+

regular expression visualization

debuggex demo

java example:

string input = "foobar foo bar 'foobar' 'foo bar' 'foo''bar'"; pattern pattern = pattern.compile("'(?:[^']|'')+'|[^ ]+"); matcher matcher = pattern.matcher(input); while (matcher.find()) {     string match = matcher.group();     system.out.println(match); }

ideone demo


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