windows - If Rectangle doesn't Contains Mouse Position -


i have rectangle can touch command below.

if ((mouse.leftbutton == buttonstate.pressed )&&         texturerectangle.contains((int)mousepos.x,(int)mousepos.y)) {     // action; } 

but there command "not contains", wanna else if user touch out of "texturerectangle" area?

when click rectangle both actions starts. dont know problem is.

if (mouse.leftbutton == buttonstate.pressed){     if(texturerectangle.contains((int)mousepos.x, (int)mousepos.y)) {         music1.play();     }      else{         music2.play();      } } 

my problem music1 , music2 plays @ same time if click on rectangle, want when click on rectangle music1 plays (here problem , both starts play)and when click out of rectangle should start music2 play ( case ok)

i recommend programming book / ebook , start reading it. basic computer logic stuff.

if (mouse.leftbutton == buttonstate.pressed) {     if (texturerectangle.contains((int)mousepos.x, (int)mousepos.y))     {         // inside     }     else     {         // outside     } } 

or

if (mouse.leftbutton == buttonstate.pressed) {     if (!texturerectangle.contains((int)mousepos.x, (int)mousepos.y))     {         // outside     }     else     {         // inside     } } 

Comments

Popular posts from this blog

java - How to specify maven bin in eclipse maven plugin? -

single sign on - Logging into Plone site with credentials passed through HTTP -

php - Why does AJAX not process login form? -