php - Why with this unexpected end of file error? -


im new beginner. have been working on 3 days, before ask question here. googled problem not same mine eventhought have same error. please me.

the error -

parse error: syntax error, unexpected end of file in c:\xampp2\htdocs\li\assignment1\edit_projek3.php on line 33 line 33, it's mean last line.

    <html> <head><title>edit projek</title></head> <body> <?php $dbcon = mysql_connect("localhost","user",""); if(!$dbcon){ die("tidak berjaya disambungkan: " . mysql_error()); } mysql_select_db("dbpelanggan",$dbcon); if(isset($_post['update'])){ $updateproject = "update projek set kod_projek='$_post[kodbaru], tajuk_projek='$_post[tajukbaru]', norujukan='$_post[rujukanbaru]' kod_projek='$_post[hidden]'"; mysql_query($updateproject, $dbcon); $listproject = "select * projek"; $queryproject = mysql_query($listproject,$dbcon); echo "<table border='0' cellpadding='1' cellspacing='1'> <tr> <th>kod projek</th> <th>tajuk projek</th> <th>no rujukan</th> </tr>"; while($record = mysql_fetch_array($queryproject)){ echo "<form action=edit_projek3.php method=post>"; echo "<tr>"; echo "<td>" . "<input type=text name=kodbaru value=" . $record['kod_projek'] . " </td>"; echo "<td>" . "<input type=text name=kodbaru value=" . $record['kod_projek'] . " </td>"; echo "<td>" . "<input type=text name=kodbaru value=" . $record['kod_projek'] . " </td>"; echo "<td>" . "<input type=text name=kodbaru value=" . $record['kod_projek'] . " </td>"; echo "<td>" . "<input type=text name=kodbaru value=" . $record['kod_projek'] . " </td>"; echo "</form>"; } ?> </body> </html>

thanks in advance.

this error saying have not close 1 bracket. have not close if(isset($_post['update'])){ bracket. use code below

 <html> <head><title>edit projek</title></head> <body> <?php $dbcon = mysql_connect("localhost","user",""); if(!$dbcon){ die("tidak berjaya disambungkan: " . mysql_error()); } mysql_select_db("dbpelanggan",$dbcon); if(isset($_post['update'])){ $updateproject = "update projek set kod_projek='$_post[kodbaru], tajuk_projek='$_post[tajukbaru]', norujukan='$_post[rujukanbaru]' kod_projek='$_post[hidden]'"; mysql_query($updateproject, $dbcon); $listproject = "select * projek"; $queryproject = mysql_query($listproject,$dbcon); echo "<table border='0' cellpadding='1' cellspacing='1'> <tr> <th>kod projek</th> <th>tajuk projek</th> <th>no rujukan</th> </tr>"; while($record = mysql_fetch_array($queryproject)){ echo "<form action=edit_projek3.php method=post>"; echo "<tr>"; echo "<td>" . "<input type=text name=kodbaru value=" . $record['kod_projek'] . " </td>"; echo "<td>" . "<input type=text name=kodbaru value=" . $record['kod_projek'] . " </td>"; echo "<td>" . "<input type=text name=kodbaru value=" . $record['kod_projek'] . " </td>"; echo "<td>" . "<input type=text name=kodbaru value=" . $record['kod_projek'] . " </td>"; echo "<td>" . "<input type=text name=kodbaru value=" . $record['kod_projek'] . " </td>"; echo "</form>"; } } ?> </body> </html>

hope helps you


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