Ruby Option Parser. Is there more concision possible for this code? -


i've written working script has several command line options. want make few of these options required options. research got me following code. you'll see @ end of script i'm checking separately options have been supplied.

in python, argparse module has argument "required=true" automatically exit program if given argument supplied. couldn't find in ruby module. there different, more advanced argument parsing module? there more concise way write code? 

options = {}  optparse = optionparser.new |opts|   opts.banner = "\nusage: how use code"   opts.on('--debug',       "change log level debug. default info") |l|     options[:debug] = l   end    options[:logfile] = "stage_refresh.out"   opts.on('-l', '--logfile logfile', "logfile log results. default stage_refresh.out") |l|     options[:source] = l   end    options[:source] = "localhost"   opts.on('-s', '--source source_host', "source host dump. default localhost") |s|     options[:source] = s   end    opts.on('-t', '--target target', "target host refresh. must specify.") |t|     options[:target] = t   end end  optparse.parse!  unless options[:source_pass]   puts "must have --source_pass password" end  unless options[:target]   puts "must have --target target_server" end  if options[:debug]   logger.level = logger::debug else   logger.level = logger::info end  puts options[:source_pass] puts options[:target]

.................

the trollop gem might of interest you. has long/short options, default values, required flags, etc. use of not unlike have right now.


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