php - Use Jquery to getJSON data feed, and display multiple json array objects in HTML -


i using jquery , getjson data feed constructed php. feed displays fine when visiting php page. problem running json feed returns multiple objects when requested in jquery, , don't know how write jquery display objects , data.

jquery:

$(document).ready(function () {     $("#display_results").hide();     $("#searchbutton").click(function (event) {         $("#display_results").show();         event.preventdefault();         search_ajax_way();     });     $("#search_results").slideup();     $("#searchbox").keyup(function (event) {         $("#display_results").show();     }); });  function search_ajax_way() {     //var search_this=$("#searchbox").val();     //$.post("http:/url.com/folder/cl/feed.php", {city : search_this},         function(data){     //$("#display_results").html(data);     //});     var search_this = $("#searchbox").val();     $.getjson('http://url.com/app/cl/disp_byowner_feed.php', {         city: search_this     }, function (result) {         $.each(result, function (i, r) {             console.log(r.seller);             window.title = r.title;             window.seller = r.seller;             window.loc = r.location;             (plan on listing keys listed in data feed below here)         });         console.log(result);         $("#display_results").html(window.seller + < need list keys / values here > );     }); }

php (constructs json feed):

$city = 'kanosh'; $s = "select * `list` `city` '%".$city."%'"; $res = $mysqli->query($s) or trigger_error($mysqli->error."[$s]"); $a = array();  while($row = $res->fetch_array(mysqli_both)) {  $a[] = array( 'title' => $row['title'], 'price' => $row['price'], 'rooms' => $row['rooms'], 'dimensions' => $row['dimensions'], 'location' => preg_replace('pic\u00a0map', '', $row['location']), 'price' => $row['price'], 'address' => $row['address'], 'seller' => $row['seller'], 'href' => $row['href'], 'date' => $row['date'] );  } header('content-type: application/json'); echo json_encode($a); $res->free(); $mysqli->close();

sample json feed:

[{     "title": "great ski-in location seller financing available ",     "price": "  (park city near resort)   ",     "rooms": "",     "dimensions": "",     "location": "",     "address": "crescent road @ 3 kings dri",     "seller": "real estate - owner",     "href": "http:\/\/saltlakecity.craigslist.org",     "date": "20140811223115" }, {     "title": "prospector building 1 - tiny condo, great location - owner financing",     "price": "$75000",     "rooms": false,     "dimensions": "",     "location": "  prospector square park city ut",     "address": "",     "seller": "real estate - owner",     "href": "http:\/\/saltlakecity.craigslist.org",     "date": "20140811223115" }]

your output array of json objects. fortunately, javascript convenient manipulating json (actually, why json created..), , jquery convenient manipulating dom.

to parse result, can iterate through array, construct whatever html string need within array, , insert dom using jquery.

here simple example lists :

var html = "";  (var = 0; < result.length; i++) { //assuming result in json array      html += '<ul id = 'house_' + i>';     (var property in result[i]) { //read object properties         html += '<li>' + property + ' : ' + result[i][property] + '</li>';      }     html += '</ul>';  };  $("whatever_div").html(html);

if want display of properties, can read them separately , additional formatting (for date example). useful give different html objects ids corresponding represent.


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