bash - How to find and replace, skipping lines containing a particular character? -


i using sed find , replace first appearance of pattern in file:

sed -i "0,\#pattern#s##replacement#" ./file.txt

how can tell skip of lines containing {. here sample input:

this line not have item, skipped. line has pattern, has {, skipped too. line has pattern, , not character, changed.

here sample output:

this line not have item, skipped. line has pattern, has {, skipped too. line has replacement, , not character, changed.
  • only 1 change made in entire file.
  • if every line pattern contains {, no changes made file.

how can use sed find , replace first appearance of item, skipping lines contain pattern, in case {?

this might work (gnu sed):

sed '/{/b;/pattern/{s//replacement/;:a;n;ba}' file

skips lines containing { on matching first pattern, substitutes replacement prints remaining lines end-of-file.


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