autocomplete - Get autocompletion list in bash variable -


i'm working big software project many build targets. when typing make <tab> <tab> shows on 1000 possible make targets. want bash script filters targets rules. therefore have list of make targets in bash variable.

make_targets=$(???) [do make_targets] make $make_targets

it best if wouldn't have change project.

how can such list?

@yuyichao created function autocomplete output:

comp() {     comp_line="$*"     comp_words=("$@")     comp_cword=${#comp_words[@]}     ((comp_cword--))     comp_point=${#comp_line}     comp_wordbreaks='"'"'><=;|&(:"     # don't thing real autocompletion script rely on     # following 2 vars, on principle ~~~  lol.     comp_type=9     comp_key=9     _command_offset 0     echo ${compreply[@]} }

just run comp make '' results, , can manipulate that. example:

$ comp make '' test foo clean

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