mysql - How to write a bash function to wrap another command? -

i trying write function wrapper mysql command

if .my.cnf exists in pwd, automatically attach --defaults-file=.my.cnf command

here's i'm trying

function mysql {   if [ -e ".my.cnf" ];     /usr/local/bin/mysql --defaults-file=.my.cnf "$@"   else     /usr/local/bin/mysql "$@"   fi } 

the idea is, want able use mysql command exactly before, only, if .my.cnf file present, attach argument

question: run trouble method? there better way it?

if specify --defaults-file=foo.cnf manually, should used instead of .my.cnf.

your function written fine. touch dryer:

function mysql {     if [ -e ".my.cnf" ];         set -- --defaults-file=.my.cnf "$@"     fi     /usr/local/bin/mysql "$@" } 

that set command puts my.cnf argument @ beginning of command line arguments

only if option not present:

function mysql {     if [[ -e ".my.cnf" && "$*" != *"--defaults-file"* ]];         set -- --defaults-file=.my.cnf "$@"     fi     /usr/local/bin/mysql "$@" }