indexing - store indexes from a table in R -


i need in here.

i have table multiple columns. 1 varying 1 30 , 1 6. other columns have multiple values. need store indexes value 1 1st column , 1 2nd column, value 1 first column , 2 2nd column , fourth... value 2 1st column, value 2 2nd column , fourth till have indexes.

thank in advance

you can use 'which' function indexes: 

y = sample(1:6, 30, replace=t) x = sample(1:30, 30, replace=t)  df = data.frame(x,y) head(df)    x y 1 22 1 2 13 5 3 28 4 4 28 3 5  7 3 6 30 6  which(df$x==2) [1] 16 22 which(df$y==2) [1] 10 11 12 18 21 27

you can use simple 'for' loop multiple tests:

for(i in 1:6){     cat("indexes of",i,"in x:\n")     print(which(df$x==i))     cat("indexes of",i,"in y:\n")     print(which(df$y==i))     cat("\n") }  indexes of 1 in x: integer(0) indexes of 1 in y: [1]  1  9 14 19 24 26  indexes of 2 in x: [1] 16 22 indexes of 2 in y: [1] 10 11 12 18 21 27  indexes of 3 in x: integer(0) indexes of 3 in y: [1]  4  5 17  indexes of 4 in x: integer(0) indexes of 4 in y: [1]  3  7 13 20 23 28  indexes of 5 in x: [1] 23 indexes of 5 in y: [1]  2 15 16 29 30  indexes of 6 in x: integer(0) indexes of 6 in y: [1]  6  8 22 25

for columns:

for(i in 1:6) {for(j in 1:ncol(df)) {cat("indexes of",i,"in",names(df)[j],'\n'); print(which(df[[j]]==i))} ;cat('\n')}  indexes of 1 in x  integer(0) indexes of 1 in y  [1]  1  9 14 19 24 26 ...

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