C: Problems with using getchar and switch case to get user input for a main menu -

i know there many threads similar one, however, threads didn't me out. new c, might making silly mistake, don't know i'm doing wrong.

i trying create main menu this:

main menu:  1. play 2. reset 3. display 

when users press 1, want print play game, when 2 pressed, want print reset, , on.
however, code, when user presses 1, prints "play game", , when users presses 2 or 3, doesn't print anything.

int main(){      int input;      /*displays menu user*/      printf("main menu\n");     printf("1.play\n");     printf("2.reset\n");     printf("3.display\n");        printf("please enter something:\n");      input=getchar();      switch(input){     case'1':         printf("play game\n");         break;     case'2':         printf("reset\n");         break;     case'3':         printf("display\n");            break;     default:         printf("invalid\n");         break;     }      {         getchar();         while(input != '3');     }     return exit_success; } 

so know might making silly mistake, can't figure doing wrong. have looked @ other threads , none them have helped me.

i think looking do-while loop. want nest switch inside do-while repeatedly execute it.

also, note getchar() call consume enter typed after number.

#include <stdio.h> #include <stdlib.h>  int main(){      int input;      /*displays menu user*/      printf("main menu\n");     printf("1.play\n");     printf("2.reset\n");     printf("3.display\n");        printf("please enter something:\n");       do{         input=getchar();         getchar();         switch(input){             case'1':                 printf("play game\n");                 break;             case'2':                 printf("reset\n");                 break;             case'3':                 printf("display\n");                    break;             default:                 printf("invalid\n");                 break;         }      } while(input != '3');     return exit_success; }