Python SqlAlchemy generate table classes pragmatically -


given list of table names, i'm trying generate sqlalchemy db table classes programmatically. here do:

def generate_table_class_list(engine):     base = declarative_base(engine)     table_names = ['table_a', 'table_b']     table_classes = dict()     table in table_names:         table_classes[table] = generate_table_class(table)     return table_classes  def generate_table_class(base, table_name):     return type(table_name, (base,), dict(__tablename__ = table_name,                                           __table_args__ = {'autoload' : true}))

when run generate_table_class_list(engine), got following error messages:

/opt/packages/sqlalchemy/engine/result.pyc in first(self)     829         try:     830             if row not none:     --> 831                 return self.process_rows([row])[0]     832             else:     833                 return none  /opt/packages/sqlalchemy/engine/result.pyc in process_rows(self, rows)     759         else:     760             return [process_row(metadata, row, processors, keymap)     --> 761                     row in rows]     762      763     def fetchall(self):  typeerror: row must sequence

i used similar scripts before same version sqlalchemy , works. however, doesn't work time.

any appreciated. in advance.

well after several days researching , testing, figure out. when create engine, set cursor class ssdictcursor. when swtiched sscursor, works fine me, though still don't why ssdictcursor breaks code.


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