c# - How to override method of base class that haven't override in signature -

today discovered interesting thing. tried define type dynamically using typebuilder , tried 'override' (i.e. replace) method defined in base class:

public class test {     public void method()     {         console.writeline("test test");     } }  public void bind(string methodtoreplace, action expr) {     @object = activator.createinstance<t>();     type objecttype = @object.gettype();     assemblybuilder asmbuilder = appdomain.currentdomain.definedynamicassembly(new assemblyname("mock"), assemblybuilderaccess.run);     modulebuilder modbuilder = asmbuilder.definedynamicmodule("mock");     typebuilder tb = modbuilder.definetype(objecttype.name, typeattributes.public | typeattributes.class, objecttype);     var mb = tb.definemethod(methodtoreplace, methodattributes.public);     ilgenerator ilgen = mb.getilgenerator();     ilgen.emitcall(opcodes.call, expr.gettype().getmethod("invoke"), null);     ilgen.emit(opcodes.ret);     @object = (t)activator.createinstance(tb.createtype()); } 

but, unfortunetly, in defined type there two methods same name 'method', ('t' instance of dynamically defined type):

t.gettype().getmethods() {system.reflection.methodinfo[6]}     [0]: {void method()}     [1]: {void method()}     [2]: {system.string tostring()}     [3]: {boolean equals(system.object)}     [4]: {int32 gethashcode()}     [5]: {system.type gettype()} 

so question is: how add new method hides base class's implementation, equivalent using c# 'new' keyword when defining new method, e.g.:

public class test2 : test {     new public void method()     {     } } 

you can see 2 methods because used type.getmethods() without bindingflags. try use bindingflags.declaredonly.

you can see 1 method. want to.

new keyword c# thing avoid hiding base method mistake.

it force use override or new avoid warning.

if want override base merhod, use method definemethodoverride on typebuilder.