python - Swig -outdir option doesn't include the .so file -


i have small project use cmake system create python module out of c++ files. in cmakelists.txt file have swig integrated follows:

# swig part here find_package(swig required) include(${swig_use_file})  find_package(pythonlibs) include_directories(${python_include_path})  set(cmake_swig_outdir ${project_binary_dir}/../lib/foo)  set_source_files_properties(swig/interface.i properties cplusplus on) set_source_files_properties(swig/interface.i swig_flags "-includeall;-c++;-shadow") swig_add_module(foo python swig/interface.i code/foo.cpp) swig_link_libraries(foo foolib ${python_libraries})

my first question why not both foo.py and _foo.so created in location specified cmake_swig_outdir? .py file created in directory. bug of cmake useswig.cmake file? .so file still in project_binary_dir location. result, can't load module in python if location cmake_swig_outdir in python_path environment variable. solve problem either:

  1. add project_binary_dir directory python_path.
  2. copy .so file cmake_swig_outdir or create symbolic link using cmake system.
  3. don't set cmake_swig_outdir variable created in project_binary_dir , add location python_path.

but none of these seem logic thing do, cmake_swig_outdir should used output both .py , .so files. missing here?

i'm not sure why cmake_swig_outdir not affect location of .so file gets generated. however, can tell of simpler , cleaner way of indicating .so file should generated.

after swig_add_module(foo ...), cmake target called _foo gets created. can edit target's properties , change library (.so file) gets generated - set_target_properties(.. library_output_directory <so_file_output_dir>).

so in code, add set_target_properties(..) line shown below:

... swig_add_module(foo python swig/interface.i code/foo.cpp) set_target_properties(_foo properties library_output_directory ${cmake_swig_outdir}) swig_link_libraries(foo foolib ${python_libraries}) ...

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